Benjamin,
If Alastair's suggestion didn't do the trick then I'd guess that
it isn't possible to know what the error might be without looking at
the project. Please send the Studio project file(s) to your
distributor's tech support hotline.
regards,
David
On 11/12/2015 10:54, Benjamin Stobbe
wrote:
Dear
Alastair,
Thank u for answering. For sure I took the area
in the calculations so I was comparing the output of the
solar panel with the solar irradiance times the area of the
solar panel. This is why I cannot figure out the results.
Best regards,
Benjamin Stobbe
Hi
Benjamin,
Solar
irradiance has the units of [kJ/hr.m^2], i.e. energy rate
per unit square meter. It is quite likely that the
magnitude of thermal energy yield (kJ) will exceed the
integrated solar irradiance (kJ/m^2), if the surface area
of your solar panels is greater than 2-3 m^2, depending on
the thermal efficiency of the panels. Make sure you have
taken the units and area into account in your
calculations.
Energy
Analysis & Engineering –
Enabling innovation for a sustainable future
Dear
all,
During my project with the hybrid solar
panel type 50b I found out some strange behaviour
during the total yield measurements. The solar
panels produce more thermal energy than irradiance
they receive, can someone explain me how this is
possible and if maybe make a mistake somewhere.
Best regards,
Benjamin Stobbe
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David BRADLEY
Principal
Thermal Energy Systems Specialists, LLC
22 North Carroll Street - suite 370
Madison, WI 53703 USA
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d.bradley@tess-inc.com
http://www.tess-inc.com
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