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Re: [TRNSYS-users] Solar radiation data
Adnan,
If the solar radiation data that you have is the instantaneous measurement, or the average rate over the 10-minute period, in W/m2 then the conversion is:
10 W/m2 =>10 J/s.m2 * 3600 s/hr * 1 kJ/1000 J = 36 kJ/h.m2
If the data you have is the integrated total then the conversion is different:
10 W.hr/m2 => 10 J.hr/s.m2 * 1 kJ/1000 J * 3600 s/hr = 36 kJ/m2
But the radiation processor requires the rate so we must divide by the timestep of the integration period:
36 kJ/m2 / 10 minutes * 60 minutes/hr = 216 kJ/h.m2
Bottom line: make sure you know the units of the measurement which you were given.
Jeff
---
Jeff Thornton
President - TESS LLC
3 N. Pinckney Street, Suite 202, Madison WI USA 53703
Office: (608) 274-2577 Fax: (608) 278-1475
www.tess-inc.com
E-Mail: thornton@tess-inc.com
On 01/06/2019 7:47 pm, adnan rasheed via TRNSYS-users wrote:
Hello everyone,
i have a question about use of 10 min interval solar radiation data used for TYPE 9 (data reader) and TYPE 16 (radiation processor). i have 10 min interval solar radiation data in W/m2, i need to convert this data to KJ/m2/hr to used in TRNSYS. how should i do among followings...
10 W/m2 .......... 10 *1000/ 3600 = 10 * 3.6 KJ/m2/hr. or i need to convert it as
10 W/m2.......... 10 * 1000/600 = 10 * 0.6 KJ/m2/10min
Thanks in advance..
--
Adnan Rasheed
PhD Researcher
Kyungpook National University
Daegu, South Korea.
+82-102762-0105
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