Hi
Amir
i think you divide something by an input, which is not constant, and may be null, certainly at time = 0
for example, if the output you need is the division between input_a and input_b, you may write :
output = (1-EQL(Input_b,0))*input_a/(input_b+0.001*EQL(Input_b,0))
Best regards
Le 24/06/2014 13:38, Amir Nashed a écrit :
i think you divide something by an input, which is not constant, and may be null, certainly at time = 0
for example, if the output you need is the division between input_a and input_b, you may write :
output = (1-EQL(Input_b,0))*input_a/(input_b+0.001*EQL(Input_b,0))
Best regards
Adrien JEZEQUEL
Simulation Dynamique - Calculs numériques
62 rue du Bolliet
73230 SAINT-ALBAN-LEYSSE
Tél : +33(0) 479 750 029
Fax : +33(0) 479 852 122
a.jezequel@itf.biz
www.itf.biz
Simulation Dynamique - Calculs numériques
62 rue du Bolliet
73230 SAINT-ALBAN-LEYSSE
Tél : +33(0) 479 750 029
Fax : +33(0) 479 852 122
a.jezequel@itf.biz
www.itf.biz
Hello
Does anyone know why the error of "dividing by zero" occurs?I mean i noticed many times that i get this error although when i print out the denominator its value never reached zero.
Thank you
Amir
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