Re: [TRNSYS-users] Energy removed Tank Type 60

[David BRADLEY <d.bradley@tess-inc.com>]

Martin,
  One convenient way of defining the solar fraction is:

qDelivered/(qAux + qParasitics)

qDelivered would come from your adsorption chiller model, qAux would be the amount of energy delivered by the aux heater, and qParasitics would primarily be your pumping energy and the electricity required by the adsorption chiller. This method avoids having to worry at all about what is happening in the tank.
Kind regards,
 David
 

On 5/3/2014 05:23, Martin Berov wrote:

Hi to all,

I need opinion about a calculation: I have a tank Type 60 which is heated with solar collectors(heat exchanger) and it's outlet is in serial connected to auxiliary heater used to drive adsorption chiller. The return of the chiller is sent either in the tank or  again directly to the aux.heater depending from the temperature etc...

Since I want to calculate the solar fraction I need the amount of energy removed from the tank so do you think than I only need the output "Energy removed from the outlet" or I need the difference between the "Energy removed from the outlet - Energy supplied from the inlet" - since if I use this difference I never reach the required heat energy - For example having adsorption chiller with 5 kW cooling power even with aux heater of 30 kW and flow rate of 5000 kg/h I have hot energy lower than the required? 

I also use the heat, cooling and chilled energy in the control strategy

What do you think?

Kind regards

Martin

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