Re: [TRNSYS-users] KWh /m2 / year

Subject: Re: [TRNSYS-users] KWh /m2 / year

From: David BRADLEY <d.bradley@tess-inc.com>

Date: Wed, 28 Mar 2012 22:29:26 -0500

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Alex,
I would use an integrator component (Type24) to integrate the energy use over the entire year, then pass its output to an equation that divides by 3600 (to get kWh) and by 330 (to get energy per m2.)
Best,
David

On 3/28/2012 04:49, Alex Rachid wrote:

Hi All,

I am simulating a Cooling System: TYP92 with TYPE56

I stored the energy removed in KWh in an excel sheet for every hour (simulation step)

QCool in KWh =QCool KJ/h/3600

how do I calculate using the output I am attaching the cooling energy in : KWh /m2/year

Cooled area: 330 m2

(what happens if the simulation step is 0.5 hr instead of 1 hour)

Thanks in advance..

Regards

Alex
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References:

[TRNSYS-users] KWh /m2 / year
- From: Alex Rachid <wow134@hotmail.com>