S Q_heat_1 = S Q_inf (if Q_heat>0) + S Q_vent (if Q_heat>0) + S Q_trans (Eqn.1)
(Ntype 30) (Ntype 4) (Ntype 5)
from Eqn. 1 you otain the transmission losses: S Q_trans
2. Simulation without solar but with internal gains:
S Q_heat_2 = S Q_heat_1 - S Q_gains,useful (Eqn.2)
from Eqn. 2 you otain the useable internal gains: S Q_gains,useful
3. Simulation with internal and solar gains:
S Q_heat_3 = S Q_heat_2 - S Q_solar,useful (Eqn.3)
from Eqn. 3 you otain the useable solar gains: S Q_solar,useful
Regards,
Marion
-----Ursprüngliche Nachricht-----
Von:
trnsys-users-bounces@engr.wisc.edu [mailto:trnsys-users-bounces@engr.wisc.edu]
Im Auftrag von jfamailbox-i3er@yahoo.fr
Gesendet: Dienstag, 30.
Mai 2006 21:43
An: trnsys-users@engr.wisc.edu
Betreff:
[TRNSYS-users] Output
Hi All,I would like to known which part of solar and internal gains really participate to heating during winter for a zone.I mean with a heating system using a temperature threshold, a part of these gain only contribute to increase temperature above the setting. Then they don't participate to heating.If you have an idea....
Regards,
JeFF
Yahoo! Mail réinvente le mail ! Découvrez le nouveau Yahoo! Mail et son interface révolutionnaire.